Integrand size = 19, antiderivative size = 54 \[ \int \frac {\tan (c+d x)}{(a+b \sec (c+d x))^2} \, dx=-\frac {\log (\cos (c+d x))}{a^2 d}-\frac {\log (a+b \sec (c+d x))}{a^2 d}+\frac {1}{a d (a+b \sec (c+d x))} \]
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Time = 0.05 (sec) , antiderivative size = 54, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 2, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.105, Rules used = {3970, 46} \[ \int \frac {\tan (c+d x)}{(a+b \sec (c+d x))^2} \, dx=-\frac {\log (a+b \sec (c+d x))}{a^2 d}-\frac {\log (\cos (c+d x))}{a^2 d}+\frac {1}{a d (a+b \sec (c+d x))} \]
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Rule 46
Rule 3970
Rubi steps \begin{align*} \text {integral}& = \frac {\text {Subst}\left (\int \frac {1}{x (a+x)^2} \, dx,x,b \sec (c+d x)\right )}{d} \\ & = \frac {\text {Subst}\left (\int \left (\frac {1}{a^2 x}-\frac {1}{a (a+x)^2}-\frac {1}{a^2 (a+x)}\right ) \, dx,x,b \sec (c+d x)\right )}{d} \\ & = -\frac {\log (\cos (c+d x))}{a^2 d}-\frac {\log (a+b \sec (c+d x))}{a^2 d}+\frac {1}{a d (a+b \sec (c+d x))} \\ \end{align*}
Time = 0.03 (sec) , antiderivative size = 54, normalized size of antiderivative = 1.00 \[ \int \frac {\tan (c+d x)}{(a+b \sec (c+d x))^2} \, dx=-\frac {b+b \log (b+a \cos (c+d x))+a \cos (c+d x) \log (b+a \cos (c+d x))}{a^2 d (b+a \cos (c+d x))} \]
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Time = 0.50 (sec) , antiderivative size = 49, normalized size of antiderivative = 0.91
method | result | size |
derivativedivides | \(\frac {-\frac {\ln \left (a +b \sec \left (d x +c \right )\right )}{a^{2}}+\frac {1}{a \left (a +b \sec \left (d x +c \right )\right )}+\frac {\ln \left (\sec \left (d x +c \right )\right )}{a^{2}}}{d}\) | \(49\) |
default | \(\frac {-\frac {\ln \left (a +b \sec \left (d x +c \right )\right )}{a^{2}}+\frac {1}{a \left (a +b \sec \left (d x +c \right )\right )}+\frac {\ln \left (\sec \left (d x +c \right )\right )}{a^{2}}}{d}\) | \(49\) |
risch | \(\frac {i x}{a^{2}}+\frac {2 i c}{a^{2} d}-\frac {2 b \,{\mathrm e}^{i \left (d x +c \right )}}{a^{2} d \left (a \,{\mathrm e}^{2 i \left (d x +c \right )}+2 b \,{\mathrm e}^{i \left (d x +c \right )}+a \right )}-\frac {\ln \left ({\mathrm e}^{2 i \left (d x +c \right )}+\frac {2 b \,{\mathrm e}^{i \left (d x +c \right )}}{a}+1\right )}{a^{2} d}\) | \(99\) |
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Time = 0.29 (sec) , antiderivative size = 46, normalized size of antiderivative = 0.85 \[ \int \frac {\tan (c+d x)}{(a+b \sec (c+d x))^2} \, dx=-\frac {{\left (a \cos \left (d x + c\right ) + b\right )} \log \left (a \cos \left (d x + c\right ) + b\right ) + b}{a^{3} d \cos \left (d x + c\right ) + a^{2} b d} \]
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\[ \int \frac {\tan (c+d x)}{(a+b \sec (c+d x))^2} \, dx=\begin {cases} \frac {\tilde {\infty } x \tan {\left (c \right )}}{\sec ^{2}{\left (c \right )}} & \text {for}\: a = 0 \wedge b = 0 \wedge d = 0 \\\frac {\log {\left (\tan ^{2}{\left (c + d x \right )} + 1 \right )}}{2 a^{2} d} & \text {for}\: b = 0 \\- \frac {1}{2 b^{2} d \sec ^{2}{\left (c + d x \right )}} & \text {for}\: a = 0 \\\frac {\int \frac {\tan {\left (c + d x \right )}}{\cos ^{2}{\left (c + d x \right )} \sec ^{2}{\left (c + d x \right )} - 2 \cos {\left (c + d x \right )} \sec {\left (c + d x \right )} + 1}\, dx}{a^{2}} & \text {for}\: b = - a \cos {\left (c + d x \right )} \\\frac {x \tan {\left (c \right )}}{\left (a + b \sec {\left (c \right )}\right )^{2}} & \text {for}\: d = 0 \\- \frac {2 a \log {\left (\frac {a}{b} + \sec {\left (c + d x \right )} \right )}}{2 a^{3} d + 2 a^{2} b d \sec {\left (c + d x \right )}} + \frac {a \log {\left (\tan ^{2}{\left (c + d x \right )} + 1 \right )}}{2 a^{3} d + 2 a^{2} b d \sec {\left (c + d x \right )}} + \frac {2 a}{2 a^{3} d + 2 a^{2} b d \sec {\left (c + d x \right )}} - \frac {2 b \log {\left (\frac {a}{b} + \sec {\left (c + d x \right )} \right )} \sec {\left (c + d x \right )}}{2 a^{3} d + 2 a^{2} b d \sec {\left (c + d x \right )}} + \frac {b \log {\left (\tan ^{2}{\left (c + d x \right )} + 1 \right )} \sec {\left (c + d x \right )}}{2 a^{3} d + 2 a^{2} b d \sec {\left (c + d x \right )}} & \text {otherwise} \end {cases} \]
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Time = 0.20 (sec) , antiderivative size = 41, normalized size of antiderivative = 0.76 \[ \int \frac {\tan (c+d x)}{(a+b \sec (c+d x))^2} \, dx=-\frac {\frac {b}{a^{3} \cos \left (d x + c\right ) + a^{2} b} + \frac {\log \left (a \cos \left (d x + c\right ) + b\right )}{a^{2}}}{d} \]
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Leaf count of result is larger than twice the leaf count of optimal. 238 vs. \(2 (54) = 108\).
Time = 0.37 (sec) , antiderivative size = 238, normalized size of antiderivative = 4.41 \[ \int \frac {\tan (c+d x)}{(a+b \sec (c+d x))^2} \, dx=-\frac {\frac {{\left (a - b\right )} \log \left ({\left | a + b + \frac {a {\left (\cos \left (d x + c\right ) - 1\right )}}{\cos \left (d x + c\right ) + 1} - \frac {b {\left (\cos \left (d x + c\right ) - 1\right )}}{\cos \left (d x + c\right ) + 1} \right |}\right )}{a^{3} - a^{2} b} - \frac {a^{2} - 2 \, a b - b^{2} + \frac {a^{2} {\left (\cos \left (d x + c\right ) - 1\right )}}{\cos \left (d x + c\right ) + 1} - \frac {2 \, a b {\left (\cos \left (d x + c\right ) - 1\right )}}{\cos \left (d x + c\right ) + 1} + \frac {b^{2} {\left (\cos \left (d x + c\right ) - 1\right )}}{\cos \left (d x + c\right ) + 1}}{{\left (a^{3} - a^{2} b\right )} {\left (a + b + \frac {a {\left (\cos \left (d x + c\right ) - 1\right )}}{\cos \left (d x + c\right ) + 1} - \frac {b {\left (\cos \left (d x + c\right ) - 1\right )}}{\cos \left (d x + c\right ) + 1}\right )}} - \frac {\log \left ({\left | -\frac {\cos \left (d x + c\right ) - 1}{\cos \left (d x + c\right ) + 1} + 1 \right |}\right )}{a^{2}}}{d} \]
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Time = 14.37 (sec) , antiderivative size = 257, normalized size of antiderivative = 4.76 \[ \int \frac {\tan (c+d x)}{(a+b \sec (c+d x))^2} \, dx=\frac {2\,\mathrm {atanh}\left (\frac {a}{2\,\left (\frac {a}{2}+b+\frac {a\,\cos \left (c+d\,x\right )}{2}\right )}-\frac {a\,\cos \left (c+d\,x\right )}{2\,\left (\frac {a}{2}+b+\frac {a\,\cos \left (c+d\,x\right )}{2}\right )}\right )}{a^2\,d}-\frac {b\,\left (a+a\,\cos \left (c+d\,x\right )-2\,a\,\mathrm {atanh}\left (\frac {a}{2\,\left (\frac {a}{2}+b+\frac {a\,\cos \left (c+d\,x\right )}{2}\right )}-\frac {a\,\cos \left (c+d\,x\right )}{2\,\left (\frac {a}{2}+b+\frac {a\,\cos \left (c+d\,x\right )}{2}\right )}\right )+2\,a\,\cos \left (c+d\,x\right )\,\mathrm {atanh}\left (\frac {a}{2\,\left (\frac {a}{2}+b+\frac {a\,\cos \left (c+d\,x\right )}{2}\right )}-\frac {a\,\cos \left (c+d\,x\right )}{2\,\left (\frac {a}{2}+b+\frac {a\,\cos \left (c+d\,x\right )}{2}\right )}\right )+\frac {2\,\mathrm {atanh}\left (\frac {a}{2\,\left (\frac {a}{2}+b+\frac {a\,\cos \left (c+d\,x\right )}{2}\right )}-\frac {a\,\cos \left (c+d\,x\right )}{2\,\left (\frac {a}{2}+b+\frac {a\,\cos \left (c+d\,x\right )}{2}\right )}\right )\,\left (a^3\,d-a^3\,d\,\cos \left (c+d\,x\right )\right )}{a^2\,d}\right )}{a^2\,d\,\left (a-b\right )\,\left (b+a\,\cos \left (c+d\,x\right )\right )} \]
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